physics problem?

[master bert]

A car is traveling at a constant speed of 33m/s on a high way. at the instant this car passes an entrance ramp, a second car enters the highway from the ramp. the second car starts from rest and has a constant acceleration. what acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 2.5km away?

[nozar nazari]

The first car will reach the next exit in 75.7575 seconds
2500 = 1/2 acceleration X t^2 so 5000= acc X t^2 =(75.7575)^2.Then 2500/75.7575^2 = acceleration of the second car.
So it is 0.8712 meter/Sec^2

[niiker345]

Originally Posted by nozar nazari

The first car will reach the next exit in 75.7575 seconds
2500 = 1/2 acceleration X t^2 so 5000= acc X t^2 =(75.7575)^2.Then 2500/75.7575^2 = acceleration of the second car.
So it is 0.8712 meter/Sec^2

This is correct